Question

Need help solving a triangle

Answer 1

the diagram is in the attached file

Answer 2

b=28, a=25.5 angle c=39 degrees, need to solve for angle a

Answer 3

have you times ed it by 180 degrees that what my math teacher taught me hope it helps.

Answer 4

times what by 180 degrees?

Answer 5

b=28, a=25.5 angle c=59

Answer 6

anlge c=39* and i have to multiply that by 180?

Answer 7

yes i think

Answer 8

hmm..idk doesnt make sense

Answer 9

well have you looked at any examples

Answer 10

I think i have to use sine law

Answer 11

okay what math are you in Algebra 1 or 2

Answer 12

This is actually grade 12 physics, this just prerequisite skills...and I live in Canada so we dont go by Algebra 1 or 2

Answer 13

( http://www.mathsisfun.com/algebra/trig-sine-law.html )This website might help . oh okay well see if you can get it from this it might help.

Answer 14

\[\frac{ Sin A }{ a }=\frac{ Sin C }{ c }\]
\[\frac{ Sin \theta }{ 25.5}= \frac{ Sin 39 }{ c }\]
\[c Sin \theta= 25.5 Sin 39\]
\[c Sin \theta= 16.05\]

This is where im stuck now idk what to do next

Answer 15

I'm sorry I haven't learned that far

Answer 16

You have used the sin rule
But I think you need the cosine rule to calculate c
You can THEN use the sin rule to calculate theta

Answer 17

Use the law of cosines first.

Answer 18

okay one sec

Answer 19

find c w/ law of cosines then use this.\[\large c Sin \theta= 16.05\]

Answer 20

I got 2.2 for c? is that right?

Answer 21

That does not sound right given how large the other two sides are.

Answer 22

one sec let me calculate it again

Answer 23

how about 18.01 for c is that right?

Answer 24

okay so i got the theta to equal 63.02 degrees is that what you got too?

Answer 25

I didn't work it out, but it looks reasonable.