Question

7x/11 divided by 14xcubed/66y

Answer 1

\(\bf \cfrac{\quad \frac{a}{b}\quad }{\frac{c}{d}}\implies \cfrac{a}{b}\cdot \cfrac{d}{c}\\ \quad \\ \quad \\
\cfrac{7x}{11}\div \cfrac{14x^3}{66y}\implies \cfrac{\frac{7x}{11}}{\frac{14x^3}{66y}}\implies \cfrac{7x}{11}\cdot \cfrac{66y}{14x^3}\)

Answer 2

how do I get it to lowest terms @jdoe0001

Answer 3

\(\bf \cfrac{7x}{11}\cdot \cfrac{66y}{14x^3}\implies \cfrac{7x}{11}\cdot \cfrac{11\cdot 6y}{7\cdot 2\cdot x\cdot x^2}\)

can you cancel anything out?

Answer 4

well... did you cancel anything out? does it have anything we can cancel out? what do you think?

Answer 5

the x

Answer 6

all the like terms are going to cancel out so I am left with 6y/2x squared

Answer 7

lemme rewrite that some ...

Answer 8

\(\bf \cfrac{7x}{11}\cdot \cfrac{66y}{14x^3}\implies \cfrac{7x}{11}\cdot \cfrac{11\cdot 6y}{7\cdot 2\cdot x\cdot x^2}\implies

\cfrac{{\color{blue}{ 7}}\cdot {\color{blue}{ x}}}{{\color{blue}{ 11}}}\cdot \cfrac{{\color{blue}{ 11}}\cdot 3\cdot {\color{blue}{ 2}}\cdot y}{{\color{blue}{ 7}}\cdot {\color{blue}{ 2}}\cdot {\color{blue}{ x}}\cdot x^2}\)

what do you think now, anything we can cancel out?

Answer 9

After I cancel out the like terms I am left with 3y/x squared

Answer 10

\(\bf \cfrac{\cancel{7x}}{\cancel{11}}\cdot

\cfrac{\cancel{11}\cdot 3\cdot \cancel{2}y}{\cancel{7}\cdot \cancel{2}\cdot \cancel{x}\cdot x^2}\)

After I cancel out the like terms I am left with 3y/x squared \(\large \checkmark\)

Answer 11

\[3y \square-12y/9y cubed\]