Question

Question below

Answer 1

Welcome to OpenStudy! ^_^ Hahahahahahahaha

Answer 2

LOWL! XD you're green!!!!

Answer 3

OMG LOWL? :)))))) Hahahahaha. okay, your dad will help you here ^_^ he'll brb.

Answer 4

yay!! thank you!
lowl XD

Answer 5

Ok I believe you will need to find the F downwards for 1 and 3 and get the net force. That F is equal to the F acting on all 3 blocks and so to find a, you will have to divide by the total mass for all 3 blocks.

I think the tensions will be the forces pulling down by blocks 1 and 3 on the respective strings.

I haven't done this in a while so it's very probable that I'm wrong. v.v

Answer 6

lemme try ...
i labeled the diagram first
i set up as +y and right +x
so i you said, find the Fg
Fg1: (26 kg)(9.8m/s^2)=254.8N
Fg3: (41kg)((9.8m/s^2)=401.8N

then net force
Fnet1= m1a
Fnet1=FT1 + Fg1=FT1 + 254.8N

Fnet3=m3a
Fnet3=FT2 + Fg3= FT2 +401.8N

then,,hmm..
net force for M2 will be :
Fnet2: FT1 +FT2

then.........?