Question

A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

Answer 1

umm what is that unit "E"?

Answer 2

thats just to the 2 power

Answer 3

umm ok so \[W = F\Delta x\]
\[F=ma\]
so work is
\[W=ma\Delta x\]

Answer 4

this is pure substitution

Answer 5

thats mass times acceleration right?

Answer 6

mass times acceleration times displacement
mass in kg
acceleration in m/s^2
displacement in meters
Work is in Joules

Answer 7

it gave me 3.4 x 10 to the 6 power.
it was right thanks

Answer 8

you're welcome