Find the values of A and B
do you know how ot find the ratio of 2 SIMILAR shapes?
using proportions?
right, so ... gimme one sec
Okay, I just want to know how to set the proportion up :D
so, what you really have is 3 SIMILAR TRIANGLES 2 small ones made by the blue line, the "altitude", and the big one containing both
so, using the corresponding sides, let us use the 2 small ones first, one can say that \(\bf \cfrac{32}{a}=\cfrac{a}{2}\)
so A=64 ?
\(\bf \cfrac{32}{a}=\cfrac{a}{2}\implies 64=a^2\)
so, you'd need to take root to both sides, to get "a"
now im lost
\(\bf \cfrac{32}{a}=\cfrac{a}{2}\implies 64=a^2\implies \sqrt{64}=\sqrt{a^2}\)
nevermind i got it lol a=8
hmmm I think my big triangle might be in the wrong position.... so... lemme repost the picture
so... any ideas how to get "b"? we could use the smallest triangle and the really big one for "b" :)
i guess the proportion for B would be \[\frac{ b }{ 2 } * \frac{ 34 }{ b }\] I got the 34 from 32+2, i dont know if im right
well, if we instead trade the " * " for a " = ", you're correct :) \(\bf \cfrac{b}{2}=\cfrac{34}{b}\implies b^2=68\implies b=\sqrt{68}\implies b=2\sqrt{17}\)
oh yeah they are equal to each other lol Okay thank you so much :D
yw
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