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A 32-foot ladder leans against a building so that the top of the ladder touches the building at a point 23 feet above the ground. To the nearest tenth of a foot, how far from the bottom of the building is the bottom of the ladder? (Points : 4) 22.2 ft 27.5 ft 30.1 ft 39.4 ft
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\[x= \sqrt{32^{2}-23^{2}}\]
answer = 22.2
Use the Pythagorean theorem for this. a^2+b^2=c^2 The ladder is c The wall is b The ground is a Rearrange the equation so that you can solve for a. a^2=c^2-b^2 Substitute values. a^2=32^2+23^2 Simplify a^2=1024-529 a^2=495 Square both sides. √a^2=√495=22.2 Answer: 22.2
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