Question

I need help with x+2 divided by x-8

Answer 1

change the numerator a bit\[\frac{x+2}{x-8}=\frac{x-8+2+8}{x-8}=\frac{x-8}{x-8}+\frac{2+8}{x-8}\]
can you see what i have done?

Answer 2

no

Answer 3

i have taken away 8 from the numerator to get something that will cancel, but to keep the fraction equal i needed to add 8 as well,

now the fraction has two parts that can be evaluated separately, the first one cancels nicely

Answer 4

ok

Answer 5

so the answer is 2 over x

Answer 6

how did you get that?

Answer 7

i cross out the 8's

Answer 8

sorry math is my worst subject i'm trying to learn this algerba

Answer 9

\[\frac{x-8}{x-8}+\frac{2+8}{x-8}\]
the first fraction will cancel , but for the second one all you can do is to simplify the numerator

Answer 10

what do you get?

Answer 11

What exactly was the original question?

Answer 12

oh , now i understand the question, i thought it was something different,
lets start again.

Answer 13

\[\frac{x+2}{x-8}\]

What you need to know is that a fraction wont be defined when the denominator is zero

so what value(s) of x make x-8 equal to zero?

Answer 14

8-8=0

Answer 15

yeah when x is 8, the denominator becomes zero, and the fraction wont make sense, any number divided by zero is undefined

Answer 16

well i would just set denominator to 0 and solve for x

x-8=0
x-8+8=8
x=8

Answer 17

thank you one more problem write in lowest term a2-b2 divided by b-a

Answer 18

that is a square minus b square

Answer 19

\[\frac{a^2-b^2}{b-a}\]

Answer 20

yes

Answer 21

write the lowest term? is that really the whole question?

Answer 22

yes the answer I got is negative 1. just want to make sure it is right.

Answer 23

is there some more information? i still dont understand this question

Answer 24

a squared minus b squared divided by a minus b

Answer 25

how did you get -1?

Answer 26

I crossed out the each a's and b's and when I cross them out i gave each a one and diveded negative l by one.

Answer 27

i'm confused, the problem is( a squared minus b squared )divided by (a minus b) yes the bootom does not squared so Im not able to cross out is that what you are saying.

Answer 28

you can only cancel terms in fractions when they are factors,
(ie with multiplication, [not addition or subtraction])

Answer 29

ok

Answer 30

Cam you tell me the exact wording of this question , i think im still missing part of it

Answer 31

it only says to write in lowest terms.

Answer 32

Oh,
"Write the expression \(\frac{a^2-b^2}{b-a}\) in lowest terms"

Answer 33

yes

Answer 34

This just means you have to expand the numerator using difference of squares
a^2−b^2=(a−b)(a+b)

and then cancel the common factor (after taking the negative, to get the factor in the numerator the same as the denominator

Answer 35

how do I do that?

Answer 36

first re-write the numerator as a product of two factors (as i have above,)

Answer 37

ok

Answer 38

thank you so much for youe help. If I need any more help with equations I hope that I can adrress them to you if noone else response once again thanks.

Answer 39

yeah for next time , i will try and help for sure, but now i have to go to sleep
bye

Answer 40

bye