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Question

anonymous · Answer

$$\sqrt[5]{x^{14}}$$
A. $$x*\sqrt[5]{x^{4}}$$
B. $$x^{7}$$
C. $$x^{4}*\sqrt[5]{x^4}$$
D. $$x^2*\sqrt[5]{x^4}$$

anonymous · Answer

@ajprincess  @jojo4eva @perl @phi @plohrr

phi · Answer

x^15 means x times itself 15 times.
x*x*x*x*x*x*x*x*x*x*x*x*x*x*x


to find the 5th root of that, find groups of 5 x's
how many groups of 5 x's are there ?

anonymous · Answer

i dont know thats why im askin you

phi · Answer

can you find 5 x's multiplied together in 
x*x*x*x*x*x*x*x*x*x*x*x*x*x*x ?
(I hope you say yes)

anonymous · Answer

x*x*x*x*x*x*x*x*x*x*x*x*x*x=x
and its multiplied by its self 14 times not 15

phi · Answer

oh, ok x is multiplied by itself 14 times

put parens around each "set of 5"
(x*x*x*x*x) * (x*x*x*x*x) * (x*x*x*x)

it looks like you have 2 sets of 5 x's  (and 4 x's left over)
the groups of 5 can *come out of the radical*  (but you change them into 1 x for each group you pull out)

anonymous · Answer

hi @rameshrajn

anonymous · Answer

so its C?

phi · Answer

how many groups of 5 do you pull out of the radical ?

anonymous · Answer

three sets of five

phi · Answer

(x*x*x*x*x) * (x*x*x*x*x) * (x*x*x*x)
   1                      2                 not 5

anonymous · Answer

i need to get this done right now so can you just tell me the answer

anonymous · Answer

oh ok

perl · Answer

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