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Geometry 7 Online
OpenStudy (anonymous):

If 6 cards are drawn at random from a standard deck of 52 cards, what is the probability that exactly 2 of the cards are spades? 0.038 0.200 0.315 0.465 0.747

OpenStudy (perl):

this is hypergeometric distribution problem

OpenStudy (anonymous):

exactly two, put \[\frac{\binom{13}{2}\binom{39}{4}}{\binom{52}{6}}\] which really just restates the question

OpenStudy (anonymous):

@perl a typo i think is this called "hypergeometric"? i can never remember

OpenStudy (perl):

I think so , yes

OpenStudy (perl):

nevermind your Latex formula is cleaner

OpenStudy (anonymous):

ok i believe you @javier94 the idea is this: you have 13 spades and you are choosing 2 of them you have 39 other cards and you are choosing 4 of them by the counting principle you multiply those together, then divide by the number of ways to choose 6 out of the 52 cards notice i computed nothing, just said what you need to compute

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

i would use a calculator for the answer http://www.wolframalpha.com/input/?i=%2813+choose+2%29*%2839+choose+4%29%2F%2852+choose+6%29

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