If 6 cards are drawn at random from a standard deck of 52 cards, what is the probability that exactly 2 of the cards are spades? 0.038 0.200 0.315 0.465 0.747
this is hypergeometric distribution problem
exactly two, put \[\frac{\binom{13}{2}\binom{39}{4}}{\binom{52}{6}}\] which really just restates the question
@perl a typo i think is this called "hypergeometric"? i can never remember
I think so , yes
nevermind your Latex formula is cleaner
ok i believe you @javier94 the idea is this: you have 13 spades and you are choosing 2 of them you have 39 other cards and you are choosing 4 of them by the counting principle you multiply those together, then divide by the number of ways to choose 6 out of the 52 cards notice i computed nothing, just said what you need to compute
ok thanks
i would use a calculator for the answer http://www.wolframalpha.com/input/?i=%2813+choose+2%29*%2839+choose+4%29%2F%2852+choose+6%29
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