Question

Find the limit

Answer 1

\[\LARGE \lim_{x \rightarrow -\infty} \frac{\sqrt{x^2-4}}{3x-1927}\]

Answer 2

i guess 1/3

Answer 3

I am with @ikram002p

Answer 4

yes me too

Answer 5

Can you show me how you got there? xD

Answer 6

divide by the largest exponential factor.

Answer 7

That means divide by \(x\). and if you put the \(x\) in the square root, you have \(\sf \frac{x^2}{x^2} = \sqrt{1} = 1\)

Answer 8

the greatest power of the polynomial in numerator 2*0.5
and denominator 1
..... x/3x
take there factors as limits 1/3

Answer 9

So, you get \(\sf \frac{1}{3}\). With these types of questions, just look at the largest exponent. For instance, limit x ->∞ of \(\sf \frac{4x^2-9}{9x^2} = \frac{4}{9}\) because limit of anything going to infinity \(\frac{9}{x^2}=0\)