Question

Find the limit as x approaches negative infinity of 8/(e^x - 5)

Answer 1

Why is the answer not infinity?

Answer 2

Did you plug in -infinity?

Answer 3

Yep, e gets closer to zero, so, 1/0 is infinity.

Answer 4

You do know e^(infinity) = A really really really really really REALLY big number, right?

Answer 5

Silly mistake, I was thinking the 8 and -5 would not make a difference, then I realized I was being stupid.

Answer 6

So understand why it's 0 now? xD

Answer 7

Limit is 8/-5, as e^x would be zero, so, you're left with 8/-5

Answer 8

Actually, e^infinity =infinity >_>

Answer 9

@Loser66 how am I doing? xD

Answer 10

don't forget e^x is at denominator!!!

Answer 11

I was getting there :P
@frostyjesus make sense or no?

Answer 12

Crap, nvm, he was right it was 0 >_>