Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Can someone show me how to solve this step by step using U substitution

OpenStudy (anonymous):

OpenStudy (anonymous):

u=x^2 +5

OpenStudy (anonymous):

derrive u

OpenStudy (anonymous):

2x=du/dx

OpenStudy (anonymous):

solve for dx

OpenStudy (anonymous):

2x=du times dx

OpenStudy (anonymous):

i mean du=2xdx

OpenStudy (anonymous):

then solve for dx

OpenStudy (anonymous):

dx=du/2x

OpenStudy (anonymous):

plug u and dx back into the integral

OpenStudy (anonymous):

integral xsin(u) dx

OpenStudy (anonymous):

plug in your info

OpenStudy (anonymous):

for dx

OpenStudy (anonymous):

integral xsin(u)du/2x

OpenStudy (anonymous):

sorry hold

OpenStudy (anonymous):

u can take out a 1/ 2x to the front

OpenStudy (anonymous):

1/2x integral xsin (u)

OpenStudy (anonymous):

now integrate

OpenStudy (anonymous):

and you fet 1/2x cosx(u) +c

OpenStudy (anonymous):

plug u back into (u)

OpenStudy (anonymous):

not sure if this is right though

zepdrix (zepdrix):

Hmm I don't understand why there is x and u in your integral alexis D: I'm just a lil confused. Lemme post some notes if it will help. \[\Large\bf\sf \int\sin(\color{orangered}{x^2+5})(\color{royalblue}{x\;dx})\] \[\Large\bf\sf \color{orangered}{u=x^2+5}, \qquad\qquad\qquad \color{royalblue}{\frac{1}{2}du=x\;dx}\] Becomes:\[\Large\bf\sf \int\limits\sin(\color{orangered}{u})(\color{royalblue}{\frac{1}{2}\;du})\quad=\quad \frac{1}{2}\int\limits \sin u \;du\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!