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Mathematics 19 Online
OpenStudy (anonymous):

Simplify: -3+i/4-3i

ganeshie8 (ganeshie8):

start by finding the conjugate of denominator, multiply numerator and denominator wid it

OpenStudy (anonymous):

sorry, whats the conjugate again? i forgot

ganeshie8 (ganeshie8):

conjugate of \(a+bi\) is \(a-bi\)

OpenStudy (anonymous):

this comes under the heading of "divide" not "simplify" as there is no such mathematical operation as "simplify" it may also be called "write in standard form"

OpenStudy (anonymous):

\[\frac{-3+i}{4-3i}=\frac{-3+i}{4-3i}\times \frac{4+3i}{4+3i}\] the denominator will be \(16+9=25\) since \((a+bi)(a-bi)=a^2+b^2\) always then the real work is in the numerator

OpenStudy (anonymous):

thank you both so much! i wish i could give two medals but i'll give to ganeshie8 because he answered first!

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