Question

(2e^2-5e)+(7e-3e^2)
MEDAL REWARDED!!
Using polynomial rules.

Answer 1

sort of like the last one
lets group them together

Answer 2

OK

Answer 3

You receive the medal already. ;)

Answer 4

\[(2e^2-5e)+(7e-3e^2)\]
\[2e^2-3e^2-5e+7e\]

Answer 5

Ok

Answer 6

1e^2-2e?

Answer 7

now the like terms are together (terms with same exponent) so your final job is to compute
\[2e^2-3e^2\] and \[-5e+7e\]

Answer 8

careful with your signs there

Answer 9

Is it wrong?

Answer 10

yes
what is \(-5+7\) or if you prefer \(7-5\) ?

Answer 11

-2 or 2

Answer 12

lol no such number as "-2 or 2"
really i bet you know what \(7-5\) is

Answer 13

2

Answer 14

k good
and so \(-5e+7e=2e\) right?

Answer 15

yes

Answer 16

now how about \(2e^2-3e^2\) which is really a matter of computing \(2-3\)

Answer 17

-1e^2?

Answer 18

yes!

Answer 19

although it would make your teacher happier if you just wrote \(-e^2\) and omitted the unnecessary \(1\)

Answer 20

-1e^2+2 for the answer right?

Answer 21

final answer?
yes

Answer 22

Okay thanks :)

Answer 23

yw

Answer 24

Thanks for the medal!