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Derivative of the Inverse of a Function: Let f(2)=6, f'(2)4, and h be the inverse of f. Find h'(6).
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\[(f^{-1})'(x)=\frac{1}{f'(f^{-1}(x))}\]
and so \[(f^{-1})'(6)=\frac{1}{f'(f^{-1}(6))}\] you have all the numbers you need to compute
@satellite73 help please?
This is the last question.
Is the answer -1d+d^2?
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clear or no? \(f(2)=6\) so \(f^{-1}(6)=2\) and \(f'(2)=4\) you get \(\frac{1}{4}\)
hold on dear, let me go back and see
Okay
How do you know that \[f^-1 (6)= 2\]
you know it because you are told that \(f(2)=6\) so necessarily \(f^{-1}(6)=2\) right?
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ohhh!!! okay!
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