Give a vector parametric equation for the line through the point (-5,-5,-2) that is parallel to the line

Question

Give a vector parametric equation for the line through the point (-5,-5,-2) that is parallel to the line <-3,t,2t-5>

anonymous · Answer

This is still just $$
y=mx+b
$$But with vectors.

anonymous · Answer

Do you know how to find the slope vector for $\langle -3,t,2t-5\rangle $?

anonymous · Answer

Hint: derivative

anonymous · Answer

Once you have that slope vector $m$, then the line is just going to be $$
mt + \langle -5,-5,-2 \rangle
$$

anonymous · Answer

$t$ is a scalar, so you'd use scalar multiplication to simplify.

majikdusty · Answer

Ohhhh wow thank you very much. When we covered this in class, all of our examples used numbers in the vector, so naturally I was a bit confused. I didn't think to use the derivative. Thanks again!

majikdusty · Answer

Also i got L(t)=<-5,-5,-2>+t<<0,1,2> as my answer. My professor doesn't require us to simplify it any further.

anonymous · Answer

that's correct :D

majikdusty · Answer

Thank you!:)