Question

factorise pa+pb+qa+qb

Answer 1

(p+q)(a+b)

Answer 2

p(a+b)+q(a+b)
(a+b)(p+q)

Answer 3

Find the things are in each !
Whats that thing ?P and q .
In first and 2 P .
In 3 and 4 q .
Right ?
So divided each 1 and 2 on p .
Divided 3 and 4 on q .
we have :
pa+pb = p(a+b)
Look at this example :
2*3+4*2
p is look like 2 .!
2(3+4)
ok ?!
So we had :
pa+pb=p(a+b)
and :
qa+qb=q(a+b)
so we have :
pa+pb+qa+qb=p(a+b)+q(a+b)=(p+q)(a+b)
Got it ?:)

Answer 4

pa+pb+qa+qb

See if you can follow along, just so you can see what might happen to actual numbers since it might be easier to digest:

let's say p=2, a=3, b=5, and q=7.

2*3+2*5+7*3+7*5

So now you can see on the left part here you have:

2*3 and 2*5. So this means you have three 2's and five 2's. If you add these up, you'll have eight 2's right? So we can rewrite it as:

(3+5)*2

And that's all factoring is really saying. We can do it again with the other part where you have three 7's and five 7's which is eight 7's.

(3+5)*2+(3+5)*7

So now if we call (3+5) as just 8, we can see we have two 8's and seven 8's so we can combine these just like we did earlier to get nine 8's.

(3+5)*(2+7)

And we can really quickly check to see if this is the same thing as we started with by either multiplying it back out again or by just multiplying 8 and 9 here and seeing if it's equal to the sum of those 4 terms we had earlier that had a pair of numbers multiplied.

Answer 5

Well done @Kainui !!!!
Thaaaaaaaaaaaaaaaaaaaanks !!!!!;)