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Physics 19 Online
OpenStudy (anonymous):

PLEASE HELP!!?

OpenStudy (anonymous):

OpenStudy (fantalux):

i think it will reach d and then fall back down but im not completely sure....

OpenStudy (mrnood):

if it had no initial velocity then you can see that it will 'fall down the trough A-C In doing so it converts it PE at A to KE at C It would then roll UP th eslope for C towards D, gaining PE and losing KE in the process. You can see therefore that if it had no initial velocity it would come to rest at a point between D and E - exactly level with A. SO We now add in the KE which it has initially at A - (mv^2)/2 Point E is 0.5 m above A (and above the equivalent point between D and E) SInce the motion is frictionless it will have the same KE at that point as it had at A To reach E it needs to increase its PE by rising another 0.5m So the question is - Is the re sufficient KE at A to raise the mass by 0.5m KE = (mv^2)/2 PE = mgh

OpenStudy (anonymous):

Yes, another statement of it is that the initial kinetic energy and potential energy must be greater or equal to the potential energy at E for the kinetic energy there at E to be greater than zero. (1/2) m v^2 + m g h >= m g h' ? mass cancels out (1/2) v^2 + g h >= g h' ? (1/2)(1.0)^2 + (9.8)(2.5) >= (9.8)(3.0) ?

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