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OpenStudy (anonymous):
need help placing Oxidation numbers for Pb3O4
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OpenStudy (abb0t):
You have an overall neutral charge and oxygen usually carries a -2 charge, so you have 4 of them, what number must you have to give you an overall charge for Pb?
OpenStudy (anonymous):
theres 3 pb so would you have to divive 8 by 3? cuz 4*-2=-8
OpenStudy (anonymous):
oh and sorry i took so long to answer
OpenStudy (anonymous):
according to this I have to treat Pb3 as Pb2 http://answers.yahoo.com/question/index?qid=20130525034348AA6MFHx
OpenStudy (wolfe8):
It is saying that Pb3O4 exists as a mixture of PbO and PbO2 together. So you will have 2 different Pb with different oxidation numbers. http://en.wikipedia.org/wiki/Lead%28II,IV%29_oxide
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OpenStudy (abb0t):
Yep. Transition metals are often difficult to work with. At least for me.
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