Question

How do you solve for tanxsin^2x=tanx?

Answer 1

x between 0 and 2pi

Answer 2

\[\tan x ARCsin x=\]

Answer 3

Since you have tan x on both sides, you can divide each side by tan x to simplify to sin^2 x = 1. Then square each side: sin x = 1, assuming that you don't need the negative square root. Solve sin x = 1: what angle measure gives you that?

Answer 4

Not arc sin, sorry sin^2x

Answer 5

Ok, so you can just get rid of the tan?

Answer 6

Yes.

Answer 7

factor

Answer 8

and no, you can't get rid of the tan
you will lose the obvious solution \(\tan(x)=0\) if you do

Answer 9

Wait you're right! sorry lol

Answer 10

So one answer is 90 but I have to find another?

Answer 11

\[\tan(x)\sin^2(x)=\tan(x)\]\[\tan(x)\sin^2(x)-\tan(x)=0\]
\[\tan(x)\left(\sin^2(x)-1\right)=0\] etc

Answer 12

Then you can change sin^2x-1 to cos^2x? But then what do you do with tanxcosx or is that wrong?

Answer 13

Ohh, do you set each equal to 0?