I need to make sure that I am on the right track to a question. The question is, "A rectangular pool has an area of 880 ft^2. The length is 10 ft longer than the width. Find the dimensions of the pool. Solve by completing the square. Round answers to the nearest tenth of a foot." The equation is x^2 + 10x = 880...This is what I have so far:

x^2 + 10x = 880
x^2 + 10x + 25 = 905
905= (x + 25)^2
√905= x + 25

Correct, right? However, the question states, that I need to find the dimensions of the pool, and I have to round to the nearest tenth of a foot, so what do you think?

Question

I need to make sure that I am on the right track to a question. The question is, "A rectangular pool has an area of 880 ft^2. The length is 10 ft longer than the width. Find the dimensions of the pool. Solve by completing the square. Round answers to the nearest tenth of a foot." The equation is x^2 + 10x = 880...This is what I have so far:

x^2 + 10x = 880
x^2 + 10x + 25 = 905
905= (x + 25)^2
√905= x + 25

Correct, right? However, the question states, that I need to find the dimensions of the pool, and I have to round to the nearest tenth of a foot, so what do you think?

anonymous · Answer

Please help!

anonymous · Answer

905= (x + 25)^2
should be
905= (x + 5)^2

anonymous · Answer

other than that, looks good :)

anonymous · Answer

K, thanks! :). How would I find the dimensions to the problem....I'm kind of stuck.

anonymous · Answer

area=length*width
width=x
length=10+x
area=x(10+x)=x^2+10x=880

anonymous · Answer

to find the width,
√905= x + 5
x=√905-5
to find the length:
x+10=√905+5

anonymous · Answer

So then the width would be 25.08 (rounded) and the length would be 35.08? Is that right?