Question

Solve for x:

(Log base 3 x)^2 -log base 3 (x)^4 + 3 = 0

Answer 1

I need your help @satellite73

Answer 2

first use the property of log , for the middle term, that
\(\log m^n = n\log m\)

Answer 3

Hi. This is how I tried to do it

Answer 4

2(log base3 x) - log base 3 (x)^4 + log base 3 (27) = log base 3 (1)

Answer 5

Is this correct?

Answer 6

@hartnn

Answer 7

nopes

(log m)^n is NOT n log m

log [(m)^n] is actually n log m

Answer 8

You're right.

Answer 9

(Log base 3 x)^2 - Log base 3 x^4 + 3 = 0

(Log base 3 x)^2 - 4Log base 3 x + 3 = 0

Let a=Log base 3

a^2 - 4a + 3 = 0

(a-1)(a-3)=0

a=1 therefore Log base 3 x = 1 ------------->>> x = 3

a=3 therefore Log base 3 x = 3 ------------->>> x = 27

Answer 10

yup, thats correct! god work :)