Question

Fill in the blank. In the triangle below, x = _____ and y = _____. Round your answer to two decimal places.

Answer 1

y=70
x=35 radical 3
i dont have a calculator so that is all i can tell you

Answer 2

I wanted to see it written out so I can understand how to do it

Answer 3

give me a sec

Answer 4

the triangle is half an equalatoral triangle so the short leg is half the hyponenuse and the long leg is always the short leg radical three

Answer 5

this is because the triangle is called a 30 60 90 triangle

Answer 6

Would it be that same for the triangle in my equation?

Answer 7

@willis97 ?

Answer 8

im confusing you i m sorry no it isnt

Answer 9

your triangle is not a 30 60 90 i thought is was

Answer 10

So you don't know how to get the answers?

Answer 11

yes i do i just have to get my stuff right give me a sec the computers dying

Answer 12

we are going to solve for z first so a+b=c so 90+52=z

Answer 13

they all equal 180 i explained it wrong

Answer 14

a+b+c=180
90+52+z=180

Answer 15

z = 38

Answer 16

correct

Answer 17

okay whats next

Answer 18

In any right angled triangle, for any angle:

The sine of the angle = the length of the opposite side
the length of the hypotenuse

The cosine of the angle = the length of the adjacent side
the length of the hypotenuse

The tangent of the angle = the length of the opposite side
the length of the adjacent side

Answer 19

we have to find these

Answer 20

im still studying these so im a little stumped as well

Answer 21

im getting someone who does know

Answer 22

Well, sine = 35/y
cosine = x/y
tangent = 35/x
that's all I know

Answer 23

@Loser66 @whpalmer4 @abb0t can you help?

Answer 24

sorry i couldnt help more

Answer 25

Its okay!

Answer 26

We know that \[\sin z = \frac{35}y\]and\[z = 180^\circ-52^\circ-90^\circ = 38^\circ\]So that gives us all we need to solve for \(y\):
\[\sin 38^\circ = \frac{35}{y}\]\[y = \frac{35}{\sin 38^\circ}\]Get out your calculator...

Similarly we can find \(x\) with either the definition of \(\tan\) or \(\sin\) (once we've established the value of \(y\):

\[\tan 52^\circ = \frac{x}{35}\]\[35\tan 52^\circ = x\]Or\[\sin 52^\circ = \frac{x}{y}\]\[x=y\sin 52^\circ\]