Question

evaluate this indefinite integral.

Integral ( x^2+1 / x^2) dx

Answer 1

is the problem
\[ \int \frac{x^2+1}{x^2} \ dx \]?

Answer 2

yes, It has the brackets around the fraction though

Answer 3

Divide each term in the numerator by \(x^2\).

Answer 4

x^2 ?

Answer 5

ok so x^2/x^2 is 1 right?
but 1/x^2?

Answer 6

Yes. For \(\displaystyle \int\frac{1}{x^2}~dx\), write it as \(x^{-2}\). Now you can simply use the power rule.

Answer 7

Ok so it would be 1+ x ^ -2?

Answer 8

and could you please remind me what the power rule is?

Answer 9

int x^n dx = 1/(n+1) * x^(n+1) + c

that's called the power rule

Answer 10

Ok I think I got it. thanks