The pressure in an engine cylinder increases from 7.6 atm to 13 atm as the gas is compressed from 0.50 L to 0.10 L. What is the expected cylinder temperature if the gas was initially 15°C?
I would use P1V1/T1=P2V2/T2. I think you will need to convert T to Kelvin before you plug it in.
Idk how to do this at all -.-
Ok. The P1V1/T1 side of the equation is the initial conditions. So since the pressure was originally 7.5 atm, that will be P1.
Does that make sense?
Or do you mean that you don't know where I got the equation from?
I mean i dont get chemistry at all lol
Ah. Well, it sounds like you have made it fairly far into gen chem without really knowing what you are doing. :) If you have more specific questions, I can help you on here. But if you would like more in depth tutoring, I do online tutoring for a fee. PM me if you are interested.
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