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calculate the energy, in joules and calories required to heat 25.0 g of water from 12.5 C to 25.7 C
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Energy required = Specific heat of water * mass * change in T
Where specific heat of water is 4.180 J/(g deg C)
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required to heat 38.0g of copper from 122 C to 246C in joules
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Same equation, but specific heat of copper is .385. These numbers are coming from a table in my chem book.
yes i see it now!!! thanks
Yw
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