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Mathematics 22 Online
OpenStudy (anonymous):

Algebra 2 helpp please Fan & medal (: (pic posted)

OpenStudy (anonymous):

OpenStudy (tkhunny):

What's preventing you from doing that? We're just adding fractions. \(\dfrac{u}{u-3} + \dfrac{1}{u}\) Find a common denominator and add the two fractions. We can worry about the denominator, later.

OpenStudy (anonymous):

how do i find a common denominator

OpenStudy (tkhunny):

Can you add these? \(\dfrac{2}{3} + \dfrac{4}{5}\)

OpenStudy (anonymous):

yeahh. um 1 7/15

OpenStudy (tkhunny):

How did you decide on 15 for the denominator?

OpenStudy (anonymous):

its common in both bbut theres letters so idk how to do that

OpenStudy (tkhunny):

It is not different AT ALL. Who told you that it was? \(\dfrac{2}{3} + \dfrac{4}{5} = \dfrac{2}{3}\cdot\dfrac{5}{5} + \dfrac{4}{5}\cdot\dfrac{3}{3} = \dfrac{10}{15} + \dfrac{12}{15} = \dfrac{22}{15}\) \(\dfrac{u}{u-3} + \dfrac{1}{u} = \dfrac{u}{u-3}\cdot\dfrac{u}{u} + \dfrac{1}{u}\dfrac{u-3}{u-3} = \dfrac{u^{2}}{u(u-3)} + \dfrac{u-3}{u(u-3)} = \dfrac{u^{2} + u - 3}{u(u-3)}\) It is exactly the same process. They are letters, I'll give you that, but they represent numbers. Just treat them like numbers.

OpenStudy (anonymous):

thanksss

OpenStudy (tkhunny):

Well, now you have to go get the denominator. Just reciprocal and multiply. You'll have it in no time.

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