Determine the zeros of the function x^2 − 25 = 0.
this is the difference of 2 squares \[(x -a)(x+a) = x^2 - a^2\] match your equation to the standard form above.. and you should get the answer
Factor x^2-25
I got (x-5)(x-5)=0 but that's not it
nearly (x -5)(x + 5) = 0 now you need to solve the binomial factors x - 5 = 0 x + 5 = 0 there will be 2 values of x...
oh is it 0?
nope... find the values of x that make x - 5 = 0 as well as x + 5 = 0
-5 and +5
?
thats it... well done
Can you help me more
Determine the zeros of the function 7x2 + 9x = 0.
*Determine the zeros of the function 7x^2 + 9x = 0.
ok... so you need to factor the equation... what is a common factor between 7x^2 and 9x ?
1?
well what about a letter factor...?
oh x hahaha
great so the factored form is x(7x + 9) = 0 now if either factor is zero, then the whole equation would equal zero... so 1 solution is x = 0 the other solution is 7x + 9 = 0 now just solve the equation for x
9/7 ? is that the other answer
:(
well its -9/7... so the 2 solutions are x = 0 and x = -9/7 substitute either value into the equation and you'd have zero as the answer...
okay thank you can you keep helping me?
This
ok... this is the graphical solution... the zeros... are the the points where y = 0.... find the corresponding x values... which means, read off the x values where the curve cuts the x-axis.... hope it all helps..
I don't know how to do that
the x- axis is the horizontal ... where does the curve cut the horizontal axis... there are 2 points |dw:1391627757439:dw|
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