Question

solve the following quadratic function x^2-16x+63?

Answer 1

\[X=( -b \pm \sqrt{a^2 -4ac} )\div 2c\]

Answer 2

(x - 7) • (x - 9)

Answer 3

ax2+bx+c

Answer 4

Step 1 :

Simplify x2-16x + 63

Trying to factor by splitting the middle term

1.1 Factoring x2-16x+63

The first term is, x2 its coefficient is 1
The middle term is, -16x its coefficient is -16
The last term, "the constant", is +63

Step-1 : Multiply the coefficient of the first term by the constant 1 • 63 = 63

Step-2 : Find two factors of 63 whose sum equals the coefficient of the middle term, which is -16
-63 + -1 = -64
-21 + -3 = -24
-9 + -7 = -16 That's it


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, (-9) and (-7)
x2 - 9x - 7x - 63

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-9)
Add up the last 2 terms, pulling out common factors :
7 • (x-9)
Now add up the four terms of step 3 :
(x-7) • (x-9)
Which is the desired factorization (x - 7) • (x - 9)

Answer 5

(x-7) (x-9)

Answer 6

thanks

Answer 7

welcome!

Answer 8

:)