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Mathematics 14 Online
OpenStudy (dobby1):

@phi

OpenStudy (dobby1):

|dw:1391637705421:dw|

OpenStudy (dobby1):

what is the horizontal asymptote

OpenStudy (phi):

to find a horizontal asymptote, look at the highest order terms in the top and bottom. Do you know what they are ?

OpenStudy (dobby1):

-2x^6 and 8x^6?

OpenStudy (phi):

yes. now when x gets really big, the lower orders terms are "swamped out" and don't count for much. so we just look at \[ y = \frac{-2x^6}{8x^6} \] can you simplify that ?

OpenStudy (phi):

remember, anything divided by itself is 1

OpenStudy (dobby1):

-1/4 right because the x^6 cancels its self out and -2/8 reduces into -1/4

OpenStudy (phi):

yes, you get y = -ΒΌ as you might remember, that is the equation of a horizontal line that is what your fraction gets very close to when x is big (but never reaches)

OpenStudy (dobby1):

yes I do remember but one question is that the answer to my question?

OpenStudy (dobby1):

oops never mind yes it is can you help with some more

OpenStudy (phi):

yes, a horizontal asymptote is the horizontal line the function approaches

OpenStudy (dobby1):

can you help me graph |dw:1391638488749:dw|

OpenStudy (dobby1):

@phi can you?

OpenStudy (dobby1):

I can make a new question

OpenStudy (phi):

you should make these new posts.

OpenStudy (dobby1):

ok

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