Solve for x. Picture will be drawn so please wait to answer the question. Medal will be rewarded! :D Show work or explain what to do!!!!
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I helped you on the last question you asked and you didn't even bother to respond. Why are you posting another question before finishing that one???
Unclear. Is 'x' the angle? That should be easy enough. Is 'x' the left piece of the base? Insufficient information.
@tkhunny the x is what you have to solve for @BangkokGarrett Sorry for not replying to you on my last question
If it's a piece of the base, we don't have enough info If it's the angle, use the law of cosines.
What's that interior line segment? Angle bisector? Median? Known length?
the line is the angle bisector
Oh, well that would have been helpful up front. What is your plan for solving?
Well 6 is the whole thing, so I figured that the other side of the bisector is x - 6
I honestly don't know my plan for solving
Well, that's pretty obvious. There are only two pieces and one of them is 'x'. Do you have any theorems about angle bisectors of isosceles triangles?
like what do you mean
If we consider the "BASE" to be the odd side out (the one that doesn't match length with the other two), the the "APEX" angle is the angle between the matching sides. The angle bisector from the Apex angle clearly bisects the Base. What about an angle bisector from a Base angle? Anything to know about that?
Maybe forget that it is isosceles. How about a general triangle and an angle bisector? \(\dfrac{x}{6-x}=\dfrac{6}{4}\) -- maybe? There have to be some triangles in your head?
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