Question

Use the quadratic formula to solve the equation.
x^2= 8x-35

Answer 1

x^2-8x+35=0
try to solve it and i will check it after u

Answer 2

@GreenPride

Answer 3

quadratic formula \[\frac{ -b \pm \sqrt{b^2-4ac}}{ 2a }\]\[a = 1\]\[b = -8\]\[c = 35\]

Answer 4

To use the quadratic formula, get your equation in the proper form:
\[ax^2 + bx + c = 0,\,a\ne 0\]@Abdulhameed has already done this for you. Then plug the numbers into the formula
\[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]You'll get two solutions unless \(b^2-4ac = 0\) (a perfect square)

Answer 5

When I plug it in I get a different number than 19 :/ And the answer is \[4+i \sqrt{19} and 4 - i \sqrt{19}\]

Answer 6

\[\frac{ -8 \pm \sqrt{64-140} }{ 2 }\]\[\frac{ -8 \pm \sqrt{-76} }{ 2 }\]\[-4 \pm \frac{ i \sqrt{76} }{ 2 }\]

Answer 7

Thats it ?

Answer 8

yeah, can't be simplify it anymore

Answer 9

@helpme1.2 that's not true, you can simplify it to \[4\pm i\sqrt{19}\]

\[-4\pm \frac{i\sqrt{76}}2 = -4\pm\frac{i\sqrt{2*2*19}}{2} = -4\pm\frac{i*2*\sqrt{19}}2=-4\pm i\sqrt{19}\]

Answer 10

Sorry, that should be \[4\pm i\sqrt{19}\]I copied your result, which has an incorrect sign because you didn't change the sign of \(b\) in the fraction.

Answer 11

\[a = 1,\, b = -8,\, c = 35\]\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} = \frac{-(-8) \pm\sqrt{(-8)^2-4(1)(35)}}{2(1)} \]\[=\frac{8\pm\sqrt{64-140}}{2} = 4\pm\frac{\sqrt{-76}}2 = 4\pm i\sqrt{19}\]