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In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO d 5N2 + 6H2O The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams. a. 23.7 grams b. 10.5 grams c. 73.5 grams d. 32.7 grams? I can't figure out how to solve this problem.
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4 moles of one with 6 moles of the other is the ratio. How many moles of NO in 27.8 g?
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