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-4^2 +2^-1 Express the number in a/b where a and b are integers
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\[\left( -4 \right)^{2}+2^{-1}=16+\frac{ 1 }{ 2 }=\frac{ 32+1 }{ 2 }=\frac{ 33 }{2 }\]
how did you get 1/2 and how did you get 32
that answer is wrong
\[2^{-1}=\frac{ 1 }{ 2^{1} }=\frac{ 1 }{ 2 }\] \[-4^{2}+2^{-1}=-16+\frac{ 1 }{2^{1} }=-16+\frac{ 1 }{ 2 }=\frac{ -32+1 }{ 2 }=\frac{ -31 }{2 }\]
\[-16+\frac{ 1 }{2 }=\frac{ -32 }{2 }+\frac{ 1 }{ 2 }=\frac{ -32+1 }{2 }=\frac{ -31 }{ 2 }\]
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i dont get it
so basically you have to multiply the 16 by 2 and still add 1/2?
\[\frac{ -16 }{1 }+\frac{ 1 }{2 },L.C.M.of~ denominator~ 1~and~ 2 ~is~2\]
oh i didn't even think about that
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