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A tree has a 25% chance of flowering. In a random sample of 15 trees, what is the probability that at least 4 develop flowers?
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I would calculate this: 1 - p(0) - p(1) - p(2) - p(3).
I wouldn't do P(4) + P(5) + ... P(15) :DD
Presumably we are getting P(n) from the binomial distribution.
\(\color{blue}{\text{Originally Posted by}}\) @SithsAndGiggles The probabilities themselves are binomial. If \(P(X=k)\) denotes the probability that \(k\) flowers develop, then \[P(X\ge4)=1-P(X<4)=1-\bigg(\color{red}{P(X=0)}+P(X=1)+P(X=2)+P(X=3)\bigg)\] as mentioned above. \[P(X=k)=\dbinom{15}k(0.25)^k(1-0.25)^{15-k}\] \(\color{blue}{\text{End of Quote}}\)
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