Question

Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00m . The cross-sectional area at point 2 is 4.80×10−2m2 ; at point 3, where the water is discharged, it is 1.60×10−2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.

Answer 1

Assuming that Bernoulli's equation applies, compute the volume of water ΔV that flows across the exit of the pipe in 1.00s . In other words, find the discharge rate ΔV/Δt.

Answer 2

Please post the diagram

Answer 3

http://session.masteringphysics.com/myct/itemView?assignmentProblemID=31836670

Answer 4

P + (1/2) rho v^2 + rho g y = constant. Bernoulli's equation

Use it to calculate the velocity v, then use v to get the volume flow rate
from dV/dt = v A