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Chemistry 13 Online
OpenStudy (anonymous):

Please help, What are the units of k in the following rate law? Rate = k[X][Y]^2 please explain how you get the answer and the steps.

OpenStudy (australopithecus):

k has to have units that allow Rate to have units of M/s In your equation you have M^3 if you multiply out all concentrations what units of k would you need to allow Rate to have units of M/s?

OpenStudy (anonymous):

i know the answer is 1/M^2S i just have no idea how to get the answer.

OpenStudy (australopithecus):

are you sure that is the answer? Remember units need to cancel to give you m/s, units cancel out just like numbers when divided

OpenStudy (anonymous):

well according the worksheet yes, it gives u the answers with it

OpenStudy (australopithecus):

yeah wait that is the answer, This is a third order equation, Since you need units of M/s for rate, Just multiplying/dividing out the units \[M^3*1/sM^2 = M/s\]

OpenStudy (australopithecus):

Third order reactions are rare as hell the chance of three particles colliding into each other at the same time is crazy small

OpenStudy (anonymous):

okay im sorry, what exactly is M here dude? i suck at chemistry lmao, ur gonna have to explain it like im a 10 year old lol

OpenStudy (australopithecus):

Molarity, these brackets mean molarity [ ]

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