Question

Light travelling through air (n=1.00) enters an optical fibre (n=1.15); the light is refracted and reflected. If the angle of incidence is θ1= 48.5°, what is the angle θ2 at which the light exits the side of the optical fibre (following the path labelled A)?

Answer 1

apply snells law for 1st refraction.....

Answer 2

...So Confused...

Answer 3

and get the angle of refraction for the first refraction........get the complementary angle.......use that as the angle of incidence.....apply snells law again....get theta 2....tadaa

Answer 4

hope that cleared ??

Answer 5

Thanks that makes sense and worked out (y)

Answer 6

no problem :)