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Mathematics 19 Online
OpenStudy (anonymous):

calculate the number of moles in 1.17 grams of NaCl

HanAkoSolo (jamierox4ev3r):

Hello there @meika ! just for future reference, you would want to post your question in the chemistry section of OpenStudy. For now, don't worry about it. Let's solve this problem

HanAkoSolo (jamierox4ev3r):

First of all, do you have any idea on how to start solving this problem?

OpenStudy (anonymous):

no not really

HanAkoSolo (jamierox4ev3r):

alright :) so the first step to solving a problem like this is finding the molar mass of NaCl itself. And we do that by looking at the atomic mass on a periodic table https://www.webelements.com

OpenStudy (anonymous):

ok got that

Parth (parthkohli):

Mass of Na: 23 Mass of Cl: 35.5 Mass of NaCl: 58.5

HanAkoSolo (jamierox4ev3r):

Parth >_>

Parth (parthkohli):

Oh, sorry! Continue.

OpenStudy (anonymous):

thats what i got

HanAkoSolo (jamierox4ev3r):

lol its fine xD so the atomic mass of NaCl would be that number that Parth had up there…then from there, you would set up a proportion to convert mass to moles.

HanAkoSolo (jamierox4ev3r):

so in this problem, we are given that there are 1.17 grams of NaCl. And we know that 1 mol of NaCl =58.5 grams. Now if we put this information together, we can set up a solvable proportion.

OpenStudy (anonymous):

given mass divided by the mass of 1 mole of the element?

HanAkoSolo (jamierox4ev3r):

basically..ultimately, your proportion would end up looking like this: \(\Large\frac{58.5g}{1 mol}=\Large\frac{1.17g}{x mol}\)

HanAkoSolo (jamierox4ev3r):

in this proportion , our aim is to solve for x

OpenStudy (anonymous):

ok....will u be here later? i have to leave but i really want to finish this

HanAkoSolo (jamierox4ev3r):

I'll be here later…but I can just solve this right here and now so you can see the process when you get back alright?

OpenStudy (anonymous):

ok

HanAkoSolo (jamierox4ev3r):

alright so I'll be writing the process right now… never mind me, feel free to leave if you need

HanAkoSolo (jamierox4ev3r):

So to go about solving a proportion, you cross multiply. Therefore, your proportion becomes: 58.5x=1.17 Then divide both sides by 58.5 to isolate the x variable. In the end, you should get that x=0.02 Therefore, there are \(\underline{0.02~moles}\) in 1.17 grams of NaCl

HanAkoSolo (jamierox4ev3r):

@meika please let me know if there is still anything you don't understand! If you have any questions, feel free to ask me. and one last order of business, I noticed that you're a new user sooooo….\(\Huge\bf \color{black}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{black}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{#ff7100}{Welcome~to~\color{#00B4ff}{\underline{\overline{Open}}}\color{#7cc517}{\underline{\overline{Study!!}}}}\) I hope you enjoy your stay!

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