Question

A playground is on the flat roof of a city school, 6.00 m above the street below. The vertical wall of the building is 7.00 m high, forming a 1.00 m high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 53.0° above the horizontal at a point 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. (b) Find the vertical distance by which the ball clears the wall. (c) Find the horizontal distance from the wall to the p

Answer 1

Can you draw a diagram.. :P

Answer 2

okay, but please i need a complete answer

Answer 3

No complete answers.. you ll only get help :P..

"Openstudy helps people who helps themselves" *true story*

Answer 4

okay

Answer 5

please wait for the diagram

Answer 6

here

Answer 7

ok.. fine.. so begin.. where do u think u can start with the problem?

Answer 8

get the initial velocity

Answer 9

ok.. how would u do that?

Answer 10

Vi=24 meters / cos 53 degrees (2.20 seconds)

Answer 11

Vi=18.1 m/s

Answer 12

u can clearly see, that the ball has travelled more than just 24 meters .. so you don't really know what is the horizontal distance.. so what you did is wrong!

Answer 13

But u know the vertical displacement. don't u? ;-/

Answer 14

wait, the one i solve is the initial velocity

Answer 15

yes.. but u can't solve the way you did!

Answer 16

okay

Answer 17

u realize why that is wrong, don't u?

Answer 18

no

Answer 19

cause i really don't understand physics

Answer 20

Wy don't you try in ther vertical directoin

you know the displacement, acceleration, and also time.. can u try?