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Mathematics 11 Online
OpenStudy (anonymous):

Each side of the regular hexagon below measures 8 cm. What is the area http://media.education2020.com/evresources/3111-13-03/mc024-1.jpgof the hexagon?

Parth (parthkohli):

Do you know any formula or should we be doing this right from the beginning?

Parth (parthkohli):

|dw:1391692969734:dw|

OpenStudy (anonymous):

yea

Parth (parthkohli):

Find the "?" using Pythagorean Theorem.

Parth (parthkohli):

Hmm -- I'm not so good at explaining this.

OpenStudy (anonymous):

no

OpenStudy (anonymous):

A=ns^2/4tan(180degrees/n)

OpenStudy (anonymous):

where n=number of sides and s=length of each side

OpenStudy (anonymous):

A=166.28 cm2

OpenStudy (anonymous):

i mean cm^2

OpenStudy (anonymous):

\[96\sqrt{3}\] \[192\sqrt{3}\] \[384\sqrt{3}\] \[768\sqrt{3}\] which one would be the best answer

OpenStudy (anonymous):

\[96\sqrt{3}\]

OpenStudy (anonymous):

what about this one

OpenStudy (anonymous):

What is the value of sec mc001-1.jpg in the triangle below? http://media.education2020.com/evresources/3111-13-05/mc001-2.jpg

OpenStudy (anonymous):

What is the value of sec theta in the triangle below?

OpenStudy (anonymous):

is there any choices?

OpenStudy (anonymous):

\[9/41\]

OpenStudy (anonymous):

9/40

OpenStudy (anonymous):

41/40

OpenStudy (anonymous):

41/9

OpenStudy (anonymous):

41/9 because sec theta =hypotenuse/ adjacent

OpenStudy (anonymous):

i had that but i wasnt sure

OpenStudy (anonymous):

Which equation finds the value of x in the triangle below?

OpenStudy (anonymous):

12tan20 degrees

OpenStudy (anonymous):

its not part of my choice

OpenStudy (anonymous):

what is the choices?

OpenStudy (anonymous):

i fail the test

OpenStudy (anonymous):

i send you that question before you gave me the wrong answer

OpenStudy (anonymous):

send me again the question

OpenStudy (anonymous):

i even gave you the choice for is

OpenStudy (anonymous):

the sec theta?

OpenStudy (anonymous):

Which of the following is the domain and range of csc theta? do this instead

OpenStudy (anonymous):

choices plz

OpenStudy (anonymous):

range: all real numbers

OpenStudy (anonymous):

i don't know that next question

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