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Mathematics 15 Online
OpenStudy (anonymous):

Use algebra to find the limit lim f(x) x->3+ when..... rest drawn inside :)

OpenStudy (anonymous):

|dw:1391709571458:dw| would i be using 2x+1 for the right limit?

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

what is the \(a=3\) supposed to mean? if you approach from \(3^+\) then I guess you have miswritten the lower limit am I correct?

OpenStudy (anonymous):

nevermind, I have misread it myself (-: You're on the right track, pardon me.

OpenStudy (anonymous):

oh it's based off of the format lim f(x) x-> a+ sorry i forgot to mention that haha i had already subbed it in :p and okay, so would it become 2(3) + 1 = 6=1 =7 ?

OpenStudy (mertsj):

yes

OpenStudy (mertsj):

As you get closer and closer to 3 when approaching from the right, the y value on the graph gets closer and closer to 7

OpenStudy (anonymous):

okay awesome! and so for lim f(x) x-> 3- would i be using x^2 - 2 ?

OpenStudy (anonymous):

ahh okay awesome! @Mertsj :)

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

\(x \to 3^{-1}\) zest means that \(x\) approaches 3 from the left, therefore \(x \) is smaller than 3.

OpenStudy (anonymous):

okay:) so 3^2 -2 = 9 -2 = 7? is that right? if so, that means that the entire limit is also 7 right?

OpenStudy (anonymous):

and would this be the graph of the limit? because it's continuous right?

OpenStudy (mertsj):

That is both the right and left limit but notice that the function defines f(3) as 2.

OpenStudy (mertsj):

It is not continuous because f(3) is NOT 7 according to what you posted earlier.

OpenStudy (anonymous):

ohh f(3) would be 2? so does this graph make more sense?

OpenStudy (mertsj):

No. Because the graph approaches 7 from both the right and left.

OpenStudy (anonymous):

ohh okay... hmm would it look something like this? those are the only choices my teacher put on the sheet... :/ |dw:1391710485100:dw|

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