Use algebra to find the limit lim f(x) x->3+ when..... rest drawn inside :)
|dw:1391709571458:dw| would i be using 2x+1 for the right limit?
yes
what is the \(a=3\) supposed to mean? if you approach from \(3^+\) then I guess you have miswritten the lower limit am I correct?
nevermind, I have misread it myself (-: You're on the right track, pardon me.
oh it's based off of the format lim f(x) x-> a+ sorry i forgot to mention that haha i had already subbed it in :p and okay, so would it become 2(3) + 1 = 6=1 =7 ?
yes
As you get closer and closer to 3 when approaching from the right, the y value on the graph gets closer and closer to 7
okay awesome! and so for lim f(x) x-> 3- would i be using x^2 - 2 ?
ahh okay awesome! @Mertsj :)
yes
\(x \to 3^{-1}\) zest means that \(x\) approaches 3 from the left, therefore \(x \) is smaller than 3.
okay:) so 3^2 -2 = 9 -2 = 7? is that right? if so, that means that the entire limit is also 7 right?
and would this be the graph of the limit? because it's continuous right?
That is both the right and left limit but notice that the function defines f(3) as 2.
It is not continuous because f(3) is NOT 7 according to what you posted earlier.
ohh f(3) would be 2? so does this graph make more sense?
No. Because the graph approaches 7 from both the right and left.
ohh okay... hmm would it look something like this? those are the only choices my teacher put on the sheet... :/ |dw:1391710485100:dw|
Join our real-time social learning platform and learn together with your friends!