Question

Rectangle A has an area of 9 - x2. Rectangle B has an area of x2 + x - 12. In simplest form, what is the ratio of the area of Rectangle A to the area of Rectangle B? Show your work.

Answer 1

divide the area of triangle A/B
\[\frac{ 9-x ^{2} }{ x ^{2}+x-12 }\]

Answer 2

now simplify

Answer 3

\[\frac{ (3-x)(3+x) }{ (x+4)(x-3) }\]

Answer 4

okay umm

Answer 5

\[\frac{ (3-x)(3+x) }{ -(x+4)(3-x)}\]

Answer 6

@Abdulhameed You just flip it around?

Answer 7

what do u mean?

Answer 8

well i looked at it and notice u switched the x and 3 on the bottom right and made a negative off the side on the bottom left

Answer 9

\[-\frac{ (3+x) }{(x+4) }\]

Answer 10

so thats it?

Answer 11

\[\frac{ -x-3 }{ x+4 }\]

Answer 12

that's it

Answer 13

oh okay ty

Answer 14

do u think u can help me with one more?

Answer 15

u r welcome , ok i'll do my best to help

Answer 16

Trevor is tiling his bathroom floor, which has an area that is represented as 117r4 square inches. Each tile has an area of square root of the quantity 9 r to the thirteenth power . The total number of tiles used can be represented by the expression below.
one hundred seventeen r to the fourth power, all over the square root of the quantity nine r to the thirteenth power

Answer 17

and what do i have to find in the question ??

Answer 18

Simplify the expression for the total number of tiles used.

Answer 19

@Abdulhameed

Answer 20

\[\frac{ 117r ^{4} }{ \sqrt{9r ^{13}} }\]

Answer 21

\[\sqrt{9}=3\]
so
\[\frac{ 117r ^{4} }{ 3\times \sqrt{r ^{13}}} \]

Answer 22

117/3=39
\[\frac{ 39r ^{4} }{ r ^{13/2} }\]
\[39r ^{4-13/2}\]
\[39r ^{-5/2}\]
\[\frac{ 39 }{ r ^{5/2} }\]
\[\frac{ 39 }{ \sqrt{r ^{5}}}\]

Answer 23

dat all? o:

Answer 24

yep that's all :)

Answer 25

Ty so much

Answer 26

u can skip some steps bcoz i wrote some steps to show what i did (for explanation)

Answer 27

alright ty

Answer 28

np :)