By graphing y=(x+1)^1/x, estimate lim y =(1+x)^1/x x->0 *round to one decimal place how do i determine this?
logarithm
how can I start that? would it be lim y= lim 1/x (1+x) ? x->0
ln(y) = (1/x) ln(x+1)
then use L'hospital rule
oops i put lim when i meant ln haha okay... could you please refresh me on what the L'hospital rule is? is that when it equals zero?
I think they want you to graph it.
ln(x+1)/x , applying L'hospital rule, d/dx ln(x+1) / d/dx(x)
oh like would i put y=(x+1)^1/x into wolfram?
lol, yeah they want you to graph it. Why go through all the trouble XD
yes, that would work
http://www.wolframalpha.com/input/?i=+y%3D%28x%2B1%29%5E1%2Fx is it the top or bottom graph?
like this
both are correct. But the BLUE line is the graph.
oh okay :) and @phi we need both graphs?
that you attached i mean :P
wolfram is showing a "zoomed" in version in the top one (but not much of a zoom)
I used geogebra to plot the function. If you want a good estimate of f(0), you have to zoom in...
http://www.wolframalpha.com/input/?i=+y%3D%28x%2B1%29%5E%281%2Fx%29%2C+x+%3D+0.000001 limit is actually e
ohh okay... so would it be 2.719? so about 2.7 rounded to one decimal place?
yes... I zoomed in a bit more than needed. as you can see, it is "e"
more or less, yes
okay, and e=2.7?
no, e is an irrational number. But approximately 2.8
at least in this case?
ohh okay thanks you guys!!
oops i mean approximately 2.7 but yea, in this case, you can say 2.7
haha okie :)thanks!
if interested, see http://www.khanacademy.org/economics-finance-domain/core-finance/interest-tutorial/cont-comp-int-and-e/v/e-as-limit
thanks for the link! it was a great video! So it looks like the value of e is basically 2.718.... haha... it's like pi all over again!! hahaa :p
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