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Mathematics 16 Online
OpenStudy (loser66):

What is standard basis of C^3? Please

OpenStudy (zzr0ck3r):

the same

OpenStudy (zzr0ck3r):

any field, will have the same basis, just different scalers...

OpenStudy (loser66):

same with what? you mean (1,0) , (0,1)?

OpenStudy (zzr0ck3r):

well, (1,0,0),(0,1,0),(0,0,1)

OpenStudy (zzr0ck3r):

C^3

OpenStudy (loser66):

if I have x =(1,1,1) in C^3, then x must be expressed under the form of (complex, complex, complex) right? so what are they?

OpenStudy (zzr0ck3r):

e_1+e_2+e_3

OpenStudy (zzr0ck3r):

im confused by the question I think....

OpenStudy (loser66):

Me too, I know x = (complex, complex, complex) and complex field has the basis (1,0) (0,i) but not sure ,

OpenStudy (zzr0ck3r):

(1+0i,1+0i,1+0i)?

OpenStudy (loser66):

if (\(\xi_1, \xi_2, \xi_3\)) is basis of C^3 then x = \(a\xi_1+b\xi_2 + c\xi_3\) so, that 's why I make the question. Thanks for the link, I went there but not clear.

OpenStudy (zzr0ck3r):

I think the problem is using (0,i) for a basis, you want (0,1) you can get to any vector in c^3 with a(1,0,0)+b(0,1,0)+c(0,0,1) where a,b,c are in C

OpenStudy (zzr0ck3r):

(0,i) is not a unit vector.

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