What is standard basis of C^3? Please
the same
any field, will have the same basis, just different scalers...
same with what? you mean (1,0) , (0,1)?
well, (1,0,0),(0,1,0),(0,0,1)
C^3
if I have x =(1,1,1) in C^3, then x must be expressed under the form of (complex, complex, complex) right? so what are they?
e_1+e_2+e_3
im confused by the question I think....
Me too, I know x = (complex, complex, complex) and complex field has the basis (1,0) (0,i) but not sure ,
(1+0i,1+0i,1+0i)?
if (\(\xi_1, \xi_2, \xi_3\)) is basis of C^3 then x = \(a\xi_1+b\xi_2 + c\xi_3\) so, that 's why I make the question. Thanks for the link, I went there but not clear.
I think the problem is using (0,i) for a basis, you want (0,1) you can get to any vector in c^3 with a(1,0,0)+b(0,1,0)+c(0,0,1) where a,b,c are in C
(0,i) is not a unit vector.
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