What is 1-2+3........+2005-2006+2007
1004, I think..
http://www.wolframalpha.com/input/?i=sum+i+%3D+1+to+2007+%28-1%29%5E%28i%2B1%29+i :DD
I don't think that's it. It's either 2008 or 0, I think.
it's 1004 :DD
But how would that work? If you add the first and last term, second term, second to last term, etc. etc., you would get 2008, -2008, etc. etc.
( sum of the odds) - (sum of the evens)
That would be (some multiple of 2008)-(some multiple of -2008), though, right?
what are saying? what multiple of 2008?
Because like I said earlier, when you add the first term and last term, you get 2008. When you add the second and second to last term, you get -2008. When you add the third term and third to last term, you get 2008. When you add the fourth term to the fourth to last term, you get -2008. There is a pattern.
@satellite73 Do you have any insight into this?
If you try it with just 1-2+3.........-12+13, you get 7. That suggests the answer should be [greatest number in the problem] + 1, then that divided by 2. So @sourwing you are right.
(1 + 2007) + (-2 + -2006) + (3 + 2005) + (-4 + -2004) + ... + (1003 + 1005) + (-1004)
the sums add up to 2008 and so 2008 - 1004 = 1004
the patter for the sum is like this: 2008 , -2008, 2008, -2008 so it's 2008 if n = odd, and -2008 if n = even look at the pair (1003 + 1005), n = odd, thus the sum is 2008 so 2008 - 1004 = 1004
Ah, you're right, cause 1004 is in the middle...
Thanks for your time and any troubles
we no, -1004 is in the middle. The sum adds up to 2008. 2008 - 1004 = 1004
yw
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