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OpenStudy (anonymous):
How do I do substitution method on the problem
3x-4y=10
2y=2x-6
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OpenStudy (jdoe0001):
can you solve the 2nd one for "y"? what do you get?
OpenStudy (anonymous):
I know I have to get y by its self right?
OpenStudy (jdoe0001):
yes
OpenStudy (anonymous):
ok so ...let me try it
OpenStudy (anonymous):
um if i subtract -2y its going to cancel the y out on the equal sign
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OpenStudy (jdoe0001):
yes, so you instead divide by 2 both sides
OpenStudy (jdoe0001):
\(\bf \cfrac{2y}{2}=\cfrac{2x-6}{2}\)
OpenStudy (anonymous):
whoa ok that was smart lol
OpenStudy (anonymous):
ok so 3x-4y=10 and y=2x-6
OpenStudy (anonymous):
now I do 3x-4(2x-6) = 10
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OpenStudy (jdoe0001):
well... more like .. one sec
OpenStudy (jdoe0001):
\(\bf \begin{array}{llll}
3x-4{\color{red}{ y}}=10\\
2y=2x-6\implies {\color{red}{ y}}=\cfrac{2x-6}{2}\implies\bf {\color{red}{ y}}=x-3
\end{array}\quad thus\\ \quad \\
3x-4{\color{red}{ y}}=10\implies 3x-4({\color{red}{ x-3}})=10\)
OpenStudy (j2lie):
you have to substitute the 2y=2x-6 into the 3x. Like this 3(2y=2x-6)-4y=10.
OpenStudy (anonymous):
ohh i forgot the fraction part..thank you I see it nowww
OpenStudy (jdoe0001):
yw
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OpenStudy (j2lie):
why do you have to divide 2x-6?
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