Question

if lim (6n^2)/(200-4n+kn^2)=1/2, then k=
x->inf

Answer 1

x is nowhere to be found in that expression

did you mean n instead of x?

Answer 2

yea sorry

Answer 3

that's ok

Answer 4

he can help more than i can sorry

Answer 5

Notice how the degree of the numerator (2) is equal to the degree of the denominator (also 2). So that means that as n approaches infinity, it will equal the ratio of the leading coefficients. In other words, you divide 6 by k to get 6/k, then you set this equal to the given limit 1/2 and solve for k

so...

6/k = 1/2

6*2 = k*1

12 = k

k = 12

Answer 6

its ok thank you

Answer 7

so pretty much the infinities cancel out

Answer 8

in a sense, yes

Answer 9

thanks, you are awesome. one more problem and im done for my quarter project

Answer 10

you're welcome

Answer 11

help me with my last problem plsss

Answer 12

sure, go ahead and post