Calculate the area of triangle CDE with altitude EF, given C (3, −2), D (−1, 2), E (2, 3), and F (0, 1). can someone hel me
help me please
hint: find the length of CD. This is the base b of the triangle. Then find the altitude EF. This is the height h of the triangle. Once you have those 2 pieces of info, you use the formula A = (b*h)/2
Let me know if that helps or not
it helped a lil but not that much can you tell me more please
To find the length of CD and EF, you use the distance formula \[\Large d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
Finding the length of CD Let C = (3,-2) = (x1,y1) so x1 = 3 y1 = -2 D = (-1,2) = (x1,y1) so x2 = -1 y2 = 2 Plug all this in to get... \[\Large d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\] \[\Large d = \sqrt{(3-(-1))^2+(-2-2)^2}\] \[\Large d = \sqrt{(3+1)^2+(-2-2)^2}\] \[\Large d = ???\]
ok i understand how to do that but theres four coordinates these are the answers 4 square units 6.2 square units 8 square units 8.7 square units im thinking b though
what's the length of CD?
in radical form
32 so then you square root it?
is that rite?
good, so CD is \(\Large \sqrt{32}\) units long. This is the length of the base. What's the height?
how do i do that now? i need to do the same thing again?
yes, but now using points E and F
since EF is the altitude (ie height) for base CD
ok so now i got 20 what do i do now?
that is incorrect
we have E (2, 3), and F (0, 1) so make (x1,y1) = (2,3) (x2,y2) = (0,1)
tell me what you get when you plug that into \[\Large d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
oohhh im sorry i got 8 now
now wat do i do?
should be \(\Large \sqrt{8}\)
\[\Large A = \frac{b*h}{2}\] \[\Large A = \frac{(\sqrt{32})*(\sqrt{8})}{2}\] \[\Large A = ???\]
ok so its 8?
Correct, the answer is 8 square units
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