Evaluate the limit. lim x--->0 sqrt(7-x) - sqrt(7+x)/x I got 0 for the limit and my textbook says its wrong.
multiply by the conjugate
i did and i got - x/ 2sqrt(7)
you forgot you had an \(x\) in the denominator
yeah, but i canceled the -2x in the numerator by the x in the denominator...
when you cancel and \(x\) with a\(-2x\) you are left with \(-2\) not \(-x\)
do i multiply the numerator and denominator by sqrt(7-x) + sqrt(7+x)/sqrt(7-x) + sqrt(7+x)?
my textbook says the limit is -1/sqrt(7). So i am not sure what i did wrong :/
oh, nvm, i think i see my problem :)
actually, im still confused
should get \[\frac{-2}{\sqrt{7-x}+\sqrt{7+x}}\] then put \(x=0\)
ah, i see now. the 2 cancels out
you get \[\frac{-2}{\sqrt{7}+\sqrt{7}}=\frac{-1}{\sqrt7}\]
yes, lot of cancelling here
ok, thanks for your help :)
yw
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